26 lines
610 B
C++
26 lines
610 B
C++
// 定义函数, 实现字符串中某个字符的查找, 并返回字符的下标或 -1
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#include <iostream>
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using namespace std;
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int findCharAt(char str[], int size, char ch)
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{
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for (int i = 0; i < size; i++)
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{
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if (str[i] == ch)
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return i;
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else if (str[i] == '\0' && str[i] != ch)
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return -1;
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}
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}
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int main()
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{
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char str[] = "abcdefg";
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char ch;
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cout << "请输入要查找的字符: ";
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cin >> ch;
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int size = sizeof(str) / sizeof(str[0]);
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int index = findCharAt(str, size, ch);
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cout << "下标为: " << index << endl;
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return 0;
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} |