96 lines
2.5 KiB
C
96 lines
2.5 KiB
C
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/*
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编写一个程序, 创建多个线程, 每个线程负责对一个共享数组的不同部分进行排序。要求实现线程间的同步, 确保每个线程在进行排序时不会干扰其他线程的工作。
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*/
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#include <stdio.h>
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#include <pthread.h>
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#include <stdlib.h>
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#include <unistd.h>
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typedef struct array_s
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{
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int *arr; // 数组元素头指针
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int start_pos; // 起始位置
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int end_pos; // 结束位置
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pthread_mutex_t *mutex; // 互斥锁
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} ARRAY;
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void *sort(void *data)
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{
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ARRAY *array = (ARRAY *)data;
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pthread_mutex_lock(array->mutex); // 线程加锁
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printf("%ld 线程开始排序\n", pthread_self());
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for (int i = array->start_pos; i < array->end_pos; i++)
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{
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for (int j = array->start_pos; j < array->end_pos - i; j++)
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{
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if (array->arr[j] > array->arr[j + 1])
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{
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array->arr[j] ^= array->arr[j + 1];
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array->arr[j + 1] ^= array->arr[j];
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array->arr[j] ^= array->arr[j + 1];
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}
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}
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}
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pthread_mutex_unlock(array->mutex); // 线程解锁
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return NULL;
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}
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int main()
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{
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int arr[9] = {1, 4, 2, 9, 0, 5, 6, 1, 8};
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pthread_mutex_t mutex;
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pthread_mutex_init(&mutex, NULL);
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ARRAY array1 = {arr, 0, 2, &mutex};
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ARRAY array2 = {arr, 3, 5, &mutex};
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ARRAY array3 = {arr, 6, 8, &mutex};
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pthread_t t1, t2, t3;
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pthread_create(&t1, NULL, sort, &array1);
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pthread_create(&t2, NULL, sort, &array2);
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pthread_create(&t3, NULL, sort, &array3);
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pthread_join(t1, NULL);
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pthread_join(t2, NULL);
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pthread_join(t3, NULL);
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// 合并排序结果
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int merged[9];
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int i = 0;
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for (int j = array1.start_pos; j <= array1.end_pos; j++)
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{
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merged[i++] = arr[j];
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}
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for (int j = array2.start_pos; j <= array2.end_pos; j++)
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{
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merged[i++] = arr[j];
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}
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for (int j = array3.start_pos; j <= array3.end_pos; j++)
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{
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merged[i++] = arr[j];
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}
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pthread_mutex_unlock(&mutex); // 解锁
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// 创建数组结构和新线程，将合并后的数组进行排序
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ARRAY arr4 = {merged, 0, 8, &mutex};
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pthread_t t4;
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pthread_create(&t4, NULL, sort, &arr4);
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pthread_join(t4, NULL);
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// 输出排序结果
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printf("排序后的数组：");
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for (int i = 0; i < 9; i++)
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{
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printf("%d ", merged[i]);
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}
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printf("\n");
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pthread_mutex_destroy(&mutex); // 销毁互斥锁
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return 0;
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}
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