75 lines
2.5 KiB
C
75 lines
2.5 KiB
C
// 请编程，设计计算个人所得税的函数，返回应缴纳所得税的金额。免税额为3500，7级超额累进税率：
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// 全月应纳税所得额 税率 速算扣除数(元)
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// 全月应纳税额不超过1500元 3 %
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// 0
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// 全月应纳税额超过1500元至4500元 10 %
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// 105
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// 全月应纳税额超过4500元至9000元 20 %
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// 555
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// 全月应纳税额超过9000元至35000元 25 %
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// 1005
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// 全月应纳税额超过35000元至55000元 30 %
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// 2755
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// 全月应纳税额超过55000元至80000元 35 %
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// 5505
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// 全月应纳税额超过80000元 45 %
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// 13505
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#include <stdio.h>
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#include <stdlib.h> // 用于 malloc 函数调用
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// int outNums[2]; // 3.全局地址？为什么要全局地址
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int *result(int, float *, int *);
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int main()
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{
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int pretexIncome; // 税前收入
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float rates[8] = {0, 0.03, 0.1, 0.2, 0.25, 0.3, 0.35, 0.45}; // 税率数组
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int deducts[8] = {0, 0, 105, 555, 1005, 2755, 5505, 13505}; // 速算扣除数数组
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printf("请输入你的税前收入: ");
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scanf("%d", &pretexIncome);
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int *res;
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res = result(pretexIncome, rates, deducts);
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printf("你最后的所得为 %d ，你所缴纳的税额为 %d\n", res[0], res[1]);
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free(res); // 释放手动分配的内存空间
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return 0;
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}
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int *result(int pretexIncomeArgs, float *rateArgs, int *deductArgs)
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{
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int level; // 税率等级
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int tex; // 缴纳税额
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int aftertexIncome; // 税后收入
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int diff = pretexIncomeArgs - 3500; // 征税差值
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// static int outNums[2]; // 1.静态地址？为什么要静态地址 (静态变量会放在全局区，仅会在程序结束时释放)
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int *outNums = (int *)malloc(2 * sizeof(int *)); // 2.手动分配内存空间？为什么
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if (diff <= 0)
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level = 0;
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else if (diff > 0 && diff <= 1500)
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level = 1;
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else if (diff > 1500 && diff <= 4500)
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level = 2;
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else if (diff > 4500 && diff <= 9000)
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level = 3;
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else if (diff > 9000 && diff <= 35000)
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level = 4;
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else if (diff > 35000 && diff <= 55000)
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level = 5;
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else if (diff > 55000 && diff <= 80000)
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level = 6;
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else if (diff > 80000)
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level = 7;
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tex = diff * rateArgs[level] - deductArgs[level];
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aftertexIncome = pretexIncomeArgs - tex;
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outNums[0] = aftertexIncome;
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outNums[1] = tex;
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return outNums; // 返回结果数组
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} |