// 请编程，设计计算个人所得税的函数，返回应缴纳所得税的金额。免税额为3500，7级超额累进税率：
//         全月应纳税所得额 税率 速算扣除数(元)
//             全月应纳税额不超过1500元 3 %
//     0
//     全月应纳税额超过1500元至4500元 10 %
//     105
//     全月应纳税额超过4500元至9000元 20 %
//     555
//     全月应纳税额超过9000元至35000元 25 %
//     1005
//     全月应纳税额超过35000元至55000元 30 %
//     2755
//     全月应纳税额超过55000元至80000元 35 %
//     5505
//     全月应纳税额超过80000元 45 %
//     13505
#include <stdio.h>

void *result(int, double *, int *);

int main()
{
    int pretexIncome;                                             // 税前收入
    double rates[8] = {0, 0.03, 0.1, 0.2, 0.25, 0.3, 0.35, 0.45}; // 税率数组
    int deducts[8] = {0, 0, 105, 555, 1005, 2755, 5505, 13505};   // 速算扣除数数组

    printf("请输入你的税前收入: ");
    scanf("%d", &pretexIncome);

    result(pretexIncome, rates, deducts);

    // int *res = result(pretexIncome, rates, deducts);
    // printf("%d%d", res[0], res[1]);
    // printf("你最后的所得为 %d ，你所缴纳的税额为 %d\n", result(pretexIncome, rates, deducts)[1], result(pretexIncome, rates, deducts)[0]);

    return 0;
}

void *result(int pretexIncomeArgs, double *rateArgs, int *deductArgs)
{
    int level;                          // 税率等级
    int tex;                            // 缴纳税额
    int aftertexIncome;                 // 税后收入
    int diff = pretexIncomeArgs - 3500; // 征税差值
    if (diff <= 0)
        level = 0;
    else if (diff > 0 && diff <= 1500)
        level = 1;
    else if (diff > 1500 && diff <= 4500)
        level = 2;
    else if (diff > 4500 && diff <= 9000)
        level = 3;
    else if (diff > 9000 && diff <= 35000)
        level = 4;
    else if (diff > 35000 && diff <= 55000)
        level = 5;
    else if (diff > 55000 && diff <= 80000)
        level = 6;
    else if (diff > 80000)
        level = 7;

    tex = diff * rateArgs[level] - deductArgs[level];
    aftertexIncome = pretexIncomeArgs - tex;

    printf("你最后的所得为 %d ，你所缴纳的税额为 %d\n", aftertexIncome, tex);

    // int outNums[2] = {(int *)aftertexIncome, (int *)tex};
    // return *outNums; // 返回结果数组
}