68 lines
1.6 KiB
C
68 lines
1.6 KiB
C
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// 编写程序并设计函数，接收年、月、日三个整数，函数返回是这一年的第几天 【提示】使用数组的方式计算，将每月的天数放在一个数组中
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#include <stdio.h>
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int todayIs(int year, int month, int day); // 数组加 switch-case 穿透方法
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int todayIsFun2(int year, int month, int day); // 数组循环方法
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int main()
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{
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int y, m, d;
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printf("请输入年,月,日(用,分隔): ");
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scanf("%d,%d,%d", &y, &m, &d);
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printf("今天是 %d 年的第 %d 天\n", y, todayIsFun2(y, m, d));
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return 0;
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}
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int todayIs(int year, int month, int day)
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{
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int days = day;
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int months[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
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switch (month)
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{
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case 12:
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days += months[10];
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case 11:
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days += months[9];
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case 10:
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days += months[8];
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case 9:
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days += months[7];
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case 8:
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days += months[6];
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case 7:
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days += months[5];
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case 6:
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days += months[4];
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case 5:
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days += months[3];
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case 4:
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days += months[2];
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case 3:
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days += months[1];
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case 2:
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days += months[0];
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}
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// 判断是否闰年?加一天:不加
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if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
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days += 1;
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return days;
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}
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int todayIsFun2(int year, int month, int day)
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{
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int days = day;
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int months[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
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for (int i = 0; i < month - 1; i++)
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{
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days += months[i];
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}
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// 判断是否闰年?加一天:不加
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if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
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days += 1;
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return days;
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}
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