78 lines
1.9 KiB
C
78 lines
1.9 KiB
C
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// 1. 2. 编写一个程序，定义一个结构体表示日期，包括年、月和日。编写一个函数，接受两个日期作为参数，并计算并返回它们之间的天数差。
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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typedef struct date_s
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{
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int year;
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int month;
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int day;
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} DATE;
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int sumDays(int year, int month, int day)
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{
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int sum = day;
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switch (month)
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{
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case 12:
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sum += 30;
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case 11:
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sum += 31;
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case 10:
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sum += 30;
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case 9:
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sum += 31;
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case 8:
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sum += 31;
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case 7:
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sum += 30;
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case 6:
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sum += 31;
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case 5:
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sum += 30;
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case 4:
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sum += 31;
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case 3:
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sum += 28;
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case 2:
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sum += 31;
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}
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if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
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sum += 1;
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return sum;
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}
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int yearOFdays(int year1, int year2)
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{
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int sum = (abs(year1 - year2) - 1) * 365;
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int runYearCount = 0; // 闰年计数器
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int minYear = (year1 < year2) ? year1 : year2; // 找出较小的年份
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int maxYear = (year1 > year2) ? year1 : year2; // 找出较大的年份
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for (; minYear <= maxYear; minYear++)
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if ((minYear % 4 == 0 && minYear % 100 != 0) || minYear % 400 == 0)
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runYearCount++;
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sum += runYearCount; // 每多一个闰年多一天
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return sum;
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}
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int main()
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{
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DATE day1, day2;
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printf("请输入第一个日期，输入格式为 年,月,日 ");
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scanf("%d,%d,%d", &day1.year, &day1.month, &day1.day);
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printf("请输入第二个日期，输入格式为 年,月,日 ");
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scanf("%d,%d,%d", &day2.year, &day2.month, &day2.day);
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int sumdays1 = sumDays(day1.year, day1.month, day1.day);
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int sumdays2 = sumDays(day2.year, day2.month, day2.day);
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int yearMoreDays = yearOFdays(day1.year, day2.year);
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int days = abs(sumdays1 - sumdays2) + yearMoreDays;
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printf("两个日期的天数差为: %d", days);
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return 0;
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}
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