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<article class="md-content__inner md-typeset">
<h1 id="_1">向量积<a class="headerlink" href="#_1" title="Permanent link">&para;</a></h1>
<p><em>向量积是衡量相似性和计算投影的基本运算。本文涵盖内积、点积、余弦相似度、叉积和外积,这些运算支撑了 AI 中的注意力机制、嵌入和几何推理。</em></p>
<ul>
<li>
<p>我们已经看到如何相加和缩放向量。但是我们可以<em>相乘</em>两个向量吗?事实证明不止一种方法,每种方法回答不同的问题。</p>
</li>
<li>
<p><strong>内积</strong>是一个广义概念:一个接受两个向量并产生一个标量的函数。它是"相乘"向量的抽象蓝图。</p>
</li>
<li>
<p>任何内积必须满足三条规则:</p>
<ul>
<li>
<p><strong>正定性</strong><span class="arithmatex">\(\langle \mathbf{v}, \mathbf{v} \rangle \geq 0\)</span>,且仅对零向量等于零。向量与自身相乘总是给出非负结果。</p>
</li>
<li>
<p><strong>对称性</strong><span class="arithmatex">\(\langle \mathbf{u}, \mathbf{v} \rangle = \langle \mathbf{v}, \mathbf{u} \rangle\)</span>。顺序无关紧要。</p>
</li>
<li>
<p><strong>线性性</strong><span class="arithmatex">\(\langle a\mathbf{u} + b\mathbf{v}, \mathbf{w} \rangle = a\langle \mathbf{u}, \mathbf{w} \rangle + b\langle \mathbf{v}, \mathbf{w} \rangle\)</span>。它对加法和缩放具有分配性。</p>
</li>
</ul>
</li>
<li>
<p><strong>点积</strong>是最常见的内积。它是你几乎到处都会用到的具体版本。对于两个向量 <span class="arithmatex">\(\mathbf{a} = (a_1, a_2, \ldots, a_n)\)</span><span class="arithmatex">\(\mathbf{b} = (b_1, b_2, \ldots, b_n)\)</span></p>
</li>
</ul>
<div class="arithmatex">\[\mathbf{a} \cdot \mathbf{b} = a_1 b_1 + a_2 b_2 + \cdots + a_n b_n\]</div>
<ul>
<li>
<p>将匹配的分量相乘,然后全部加起来。这就是全部。</p>
</li>
<li>
<p>但这个数字<em>意味着</em>什么?点积有一个优美的几何解释:</p>
</li>
</ul>
<div class="arithmatex">\[\mathbf{a} \cdot \mathbf{b} = \|\mathbf{a}\| \, \|\mathbf{b}\| \cos(\theta)\]</div>
<p><img alt="点积:向量 a 投影到 b 上,显示角度 θ 和投影" src="../../images/dot_product.svg" /></p>
<ul>
<li>
<p>这将点积直接与两个向量之间的角度 <span class="arithmatex">\(\theta\)</span> 联系起来。结果告诉你两个向量在方向上"一致"的程度。</p>
</li>
<li>
<p>如果它们指向相同方向(<span class="arithmatex">\(\theta = 0°\)</span>),<span class="arithmatex">\(\cos(\theta) = 1\)</span> 且点积最大。</p>
</li>
<li>
<p>如果它们正交(<span class="arithmatex">\(\theta = 90°\)</span>),<span class="arithmatex">\(\cos(\theta) = 0\)</span> 且点积恰好为零。这给出了正交性的精确检验。</p>
</li>
<li>
<p>如果它们指向相反方向(<span class="arithmatex">\(\theta = 180°\)</span>),<span class="arithmatex">\(\cos(\theta) = -1\)</span> 且点积为负。</p>
</li>
<li>
<p>向量与自身的点积给出其模长的平方:<span class="arithmatex">\(\mathbf{a} \cdot \mathbf{a} = \|\mathbf{a}\|^2\)</span></p>
</li>
<li>
<p>点积还给出了<strong>投影</strong>,即一个向量在另一个向量上投下的影子。<span class="arithmatex">\(\mathbf{a}\)</span><span class="arithmatex">\(\mathbf{b}\)</span> 上的投影为:</p>
</li>
</ul>
<div class="arithmatex">\[\text{proj}_{\mathbf{b}}(\mathbf{a}) = \frac{\mathbf{a} \cdot \mathbf{b}}{\|\mathbf{b}\|^2} \, \mathbf{b}\]</div>
<ul>
<li>
<p>想象一束光线直射到 <span class="arithmatex">\(\mathbf{b}\)</span> 上。<span class="arithmatex">\(\mathbf{a}\)</span> 在那条线上的影子就是投影。它告诉你 <span class="arithmatex">\(\mathbf{a}\)</span> 有多少位于 <span class="arithmatex">\(\mathbf{b}\)</span> 的方向上。</p>
</li>
<li>
<p><strong>余弦相似度</strong>通过除以两个模长来归一化点积:</p>
</li>
</ul>
<div class="arithmatex">\[\cos(\theta) = \frac{\mathbf{a} \cdot \mathbf{b}}{\|\mathbf{a}\| \, \|\mathbf{b}\|}\]</div>
<ul>
<li>
<p>这会给出一个介于 <span class="arithmatex">\(-1\)</span><span class="arithmatex">\(1\)</span> 之间的值,衡量方向对齐程度,忽略向量的长度。它广泛应用于 ML 中来比较文档、嵌入和用户偏好等事物。</p>
</li>
<li>
<p>现在,点积接受两个向量并返回标量。<strong>叉积</strong>则相反,它接受两个向量并返回一个<em>新向量</em></p>
</li>
<li>
<p>叉积 <span class="arithmatex">\(\mathbf{a} \times \mathbf{b}\)</span> 产生一个同时垂直于 <span class="arithmatex">\(\mathbf{a}\)</span><span class="arithmatex">\(\mathbf{b}\)</span> 的向量:</p>
</li>
</ul>
<div class="arithmatex">\[\mathbf{a} \times \mathbf{b} = (a_2 b_3 - a_3 b_2, \; a_3 b_1 - a_1 b_3, \; a_1 b_2 - a_2 b_1)\]</div>
<ul>
<li>
<p>叉积只适用于三维。点积适用于任意维度,而叉积是三维空间特有的。</p>
</li>
<li>
<p>其模长等于由这两个向量形成的平行四边形的面积:</p>
</li>
</ul>
<div class="arithmatex">\[\|\mathbf{a} \times \mathbf{b}\| = \|\mathbf{a}\| \, \|\mathbf{b}\| \sin(\theta)\]</div>
<ul>
<li>
<p>注意模式:点积使用 <span class="arithmatex">\(\cos(\theta)\)</span>,叉积使用 <span class="arithmatex">\(\sin(\theta)\)</span>。点积衡量两个向量对齐的程度,叉积衡量它们在方向上<em>差异</em>的程度。</p>
</li>
<li>
<p>结果的方向遵循<strong>右手定则</strong>:将右手的手指从 <span class="arithmatex">\(\mathbf{a}\)</span> 弯向 <span class="arithmatex">\(\mathbf{b}\)</span>,拇指指向 <span class="arithmatex">\(\mathbf{a} \times \mathbf{b}\)</span> 的方向。</p>
</li>
<li>
<p>与点积不同,叉积<strong>不可交换</strong><span class="arithmatex">\(\mathbf{a} \times \mathbf{b} = -(\mathbf{b} \times \mathbf{a})\)</span>。交换顺序会翻转方向。</p>
</li>
<li>
<p>如果两个向量平行,它们的叉积是零向量(因为 <span class="arithmatex">\(\sin(0°) = 0\)</span>)。没有面积,没有垂直方向。</p>
</li>
<li>
<p>当你使用两个乘积结合三个向量会发生什么?这就得到了<strong>三重积</strong></p>
</li>
<li>
<p>xxxxxxxxxx9 1import jax.numpy as jnp23u = jnp.array([1.0, 2.0, 3.0])4v = jnp.array([4.0, 0.0, 1.0])56euclidean = jnp.sqrt(jnp.sum((u - v) ** 2))7manhattan = jnp.sum(jnp.abs(u - v))89print(f"Euclidean: {euclidean:.2f}, Manhattan: {manhattan}")python</p>
</li>
<li>
<p>如果标量三重积为零,则这三个向量<strong>共面</strong>,它们都位于同一个平坦平面上,不形成体积。</p>
</li>
<li>
<p>顺序可以循环而不改变结果:<span class="arithmatex">\(\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = \mathbf{b} \cdot (\mathbf{c} \times \mathbf{a}) = \mathbf{c} \cdot (\mathbf{a} \times \mathbf{b})\)</span></p>
</li>
<li>
<p><strong>向量三重积</strong> <span class="arithmatex">\(\mathbf{a} \times (\mathbf{b} \times \mathbf{c})\)</span> 应用两次叉积并返回一个向量。它可以使用恒等式简洁展开:</p>
</li>
</ul>
<div class="arithmatex">\[\mathbf{a} \times (\mathbf{b} \times \mathbf{c}) = (\mathbf{a} \cdot \mathbf{c})\mathbf{b} - (\mathbf{a} \cdot \mathbf{b})\mathbf{c}\]</div>
<ul>
<li>结果总是位于由 <span class="arithmatex">\(\mathbf{b}\)</span><span class="arithmatex">\(\mathbf{c}\)</span> 张成的平面内。注意叉积<strong>不满足结合律</strong><span class="arithmatex">\(\mathbf{a} \times (\mathbf{b} \times \mathbf{c}) \neq (\mathbf{a} \times \mathbf{b}) \times \mathbf{c}\)</span></li>
</ul>
<h2 id="colab-notebook">编程练习(使用 CoLab 或 notebook<a class="headerlink" href="#colab-notebook" title="Permanent link">&para;</a></h2>
<ol>
<li>
<p>计算两个向量的点积并用它求出它们之间的角度。尝试让它们正交、平行或反向,观察角度如何变化。
<div class="highlight"><pre><span></span><code><a id="__codelineno-0-1" name="__codelineno-0-1" href="#__codelineno-0-1"></a><span class="kn">import</span><span class="w"> </span><span class="nn">jax.numpy</span><span class="w"> </span><span class="k">as</span><span class="w"> </span><span class="nn">jnp</span>
<a id="__codelineno-0-2" name="__codelineno-0-2" href="#__codelineno-0-2"></a>
<a id="__codelineno-0-3" name="__codelineno-0-3" href="#__codelineno-0-3"></a><span class="n">a</span> <span class="o">=</span> <span class="n">jnp</span><span class="o">.</span><span class="n">array</span><span class="p">([</span><span class="mf">1.0</span><span class="p">,</span> <span class="mf">2.0</span><span class="p">,</span> <span class="mf">3.0</span><span class="p">])</span>
<a id="__codelineno-0-4" name="__codelineno-0-4" href="#__codelineno-0-4"></a><span class="n">b</span> <span class="o">=</span> <span class="n">jnp</span><span class="o">.</span><span class="n">array</span><span class="p">([</span><span class="mf">4.0</span><span class="p">,</span> <span class="o">-</span><span class="mf">1.0</span><span class="p">,</span> <span class="mf">2.0</span><span class="p">])</span>
<a id="__codelineno-0-5" name="__codelineno-0-5" href="#__codelineno-0-5"></a>
<a id="__codelineno-0-6" name="__codelineno-0-6" href="#__codelineno-0-6"></a><span class="n">dot</span> <span class="o">=</span> <span class="n">jnp</span><span class="o">.</span><span class="n">dot</span><span class="p">(</span><span class="n">a</span><span class="p">,</span> <span class="n">b</span><span class="p">)</span>
<a id="__codelineno-0-7" name="__codelineno-0-7" href="#__codelineno-0-7"></a><span class="n">angle</span> <span class="o">=</span> <span class="n">jnp</span><span class="o">.</span><span class="n">arccos</span><span class="p">(</span><span class="n">dot</span> <span class="o">/</span> <span class="p">(</span><span class="n">jnp</span><span class="o">.</span><span class="n">linalg</span><span class="o">.</span><span class="n">norm</span><span class="p">(</span><span class="n">a</span><span class="p">)</span> <span class="o">*</span> <span class="n">jnp</span><span class="o">.</span><span class="n">linalg</span><span class="o">.</span><span class="n">norm</span><span class="p">(</span><span class="n">b</span><span class="p">)))</span>
<a id="__codelineno-0-8" name="__codelineno-0-8" href="#__codelineno-0-8"></a>
<a id="__codelineno-0-9" name="__codelineno-0-9" href="#__codelineno-0-9"></a><span class="nb">print</span><span class="p">(</span><span class="sa">f</span><span class="s2">&quot;Dot product: </span><span class="si">{</span><span class="n">dot</span><span class="si">}</span><span class="s2">&quot;</span><span class="p">)</span>
<a id="__codelineno-0-10" name="__codelineno-0-10" href="#__codelineno-0-10"></a><span class="nb">print</span><span class="p">(</span><span class="sa">f</span><span class="s2">&quot;Angle: </span><span class="si">{</span><span class="n">jnp</span><span class="o">.</span><span class="n">degrees</span><span class="p">(</span><span class="n">angle</span><span class="p">)</span><span class="si">:</span><span class="s2">.1f</span><span class="si">}</span><span class="s2">°&quot;</span><span class="p">)</span>
</code></pre></div></p>
</li>
<li>
<p>计算两个三维向量的叉积,并通过检查结果与每个原始向量的点积为零来验证结果垂直于两者。
<div class="highlight"><pre><span></span><code><a id="__codelineno-1-1" name="__codelineno-1-1" href="#__codelineno-1-1"></a><span class="kn">import</span><span class="w"> </span><span class="nn">jax.numpy</span><span class="w"> </span><span class="k">as</span><span class="w"> </span><span class="nn">jnp</span>
<a id="__codelineno-1-2" name="__codelineno-1-2" href="#__codelineno-1-2"></a>
<a id="__codelineno-1-3" name="__codelineno-1-3" href="#__codelineno-1-3"></a><span class="n">a</span> <span class="o">=</span> <span class="n">jnp</span><span class="o">.</span><span class="n">array</span><span class="p">([</span><span class="mf">1.0</span><span class="p">,</span> <span class="mf">0.0</span><span class="p">,</span> <span class="mf">0.0</span><span class="p">])</span>
<a id="__codelineno-1-4" name="__codelineno-1-4" href="#__codelineno-1-4"></a><span class="n">b</span> <span class="o">=</span> <span class="n">jnp</span><span class="o">.</span><span class="n">array</span><span class="p">([</span><span class="mf">0.0</span><span class="p">,</span> <span class="mf">1.0</span><span class="p">,</span> <span class="mf">0.0</span><span class="p">])</span>
<a id="__codelineno-1-5" name="__codelineno-1-5" href="#__codelineno-1-5"></a>
<a id="__codelineno-1-6" name="__codelineno-1-6" href="#__codelineno-1-6"></a><span class="n">cross</span> <span class="o">=</span> <span class="n">jnp</span><span class="o">.</span><span class="n">cross</span><span class="p">(</span><span class="n">a</span><span class="p">,</span> <span class="n">b</span><span class="p">)</span>
<a id="__codelineno-1-7" name="__codelineno-1-7" href="#__codelineno-1-7"></a>
<a id="__codelineno-1-8" name="__codelineno-1-8" href="#__codelineno-1-8"></a><span class="nb">print</span><span class="p">(</span><span class="sa">f</span><span class="s2">&quot;a x b = </span><span class="si">{</span><span class="n">cross</span><span class="si">}</span><span class="s2">&quot;</span><span class="p">)</span>
<a id="__codelineno-1-9" name="__codelineno-1-9" href="#__codelineno-1-9"></a><span class="nb">print</span><span class="p">(</span><span class="sa">f</span><span class="s2">&quot;Perpendicular to a: </span><span class="si">{</span><span class="n">jnp</span><span class="o">.</span><span class="n">dot</span><span class="p">(</span><span class="n">cross</span><span class="p">,</span><span class="w"> </span><span class="n">a</span><span class="p">)</span><span class="w"> </span><span class="o">==</span><span class="w"> </span><span class="mi">0</span><span class="si">}</span><span class="s2">&quot;</span><span class="p">)</span>
<a id="__codelineno-1-10" name="__codelineno-1-10" href="#__codelineno-1-10"></a><span class="nb">print</span><span class="p">(</span><span class="sa">f</span><span class="s2">&quot;Perpendicular to b: </span><span class="si">{</span><span class="n">jnp</span><span class="o">.</span><span class="n">dot</span><span class="p">(</span><span class="n">cross</span><span class="p">,</span><span class="w"> </span><span class="n">b</span><span class="p">)</span><span class="w"> </span><span class="o">==</span><span class="w"> </span><span class="mi">0</span><span class="si">}</span><span class="s2">&quot;</span><span class="p">)</span>
</code></pre></div></p>
</li>
</ol>
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