55 lines
1.5 KiB
C++
55 lines
1.5 KiB
C++
/**
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* File: subset_sum_i_naive.cpp
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* Created Time: 2023-06-21
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* Author: krahets (krahets@163.com)
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*/
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#include "../utils/common.hpp"
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/* 回溯算法：子集和 I */
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void backtrack(vector<int> &state, int target, int total, vector<int> &choices, vector<vector<int>> &res) {
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// 子集和等于 target 时，记录解
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if (total == target) {
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res.push_back(state);
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return;
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}
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// 遍历所有选择
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for (size_t i = 0; i < choices.size(); i++) {
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// 剪枝：若子集和超过 target ，则跳过该选择
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if (total + choices[i] > target) {
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continue;
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}
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// 尝试：做出选择，更新元素和 total
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state.push_back(choices[i]);
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// 进行下一轮选择
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backtrack(state, target, total + choices[i], choices, res);
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// 回退：撤销选择，恢复到之前的状态
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state.pop_back();
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}
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}
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/* 求解子集和 I（包含重复子集） */
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vector<vector<int>> subsetSumINaive(vector<int> &nums, int target) {
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vector<int> state; // 状态（子集）
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int total = 0; // 子集和
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vector<vector<int>> res; // 结果列表（子集列表）
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backtrack(state, target, total, nums, res);
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return res;
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}
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/* Driver Code */
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int main() {
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vector<int> nums = {3, 4, 5};
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int target = 9;
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vector<vector<int>> res = subsetSumINaive(nums, target);
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cout << "输入数组 nums = ";
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printVector(nums);
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cout << "target = " << target << endl;
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cout << "所有和等于 " << target << " 的子集 res = " << endl;
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printVectorMatrix(res);
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return 0;
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}
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